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 * Version: MPL 1.1/GPL 2.0/LGPL 2.1
 *
 * The contents of this file are subject to the Mozilla Public License Version
 * 1.1 (the "License"); you may not use this file except in compliance with
 * the License. You may obtain a copy of the License at
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 * Software distributed under the License is distributed on an "AS IS" basis,
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 * for the specific language governing rights and limitations under the
 * License.
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 * The Original Code is Rhino code, released
 * May 6, 1999.
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 * The Initial Developer of the Original Code is
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 * Portions created by the Initial Developer are Copyright (C) 1997-2000
 * the Initial Developer. All Rights Reserved.
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 * Contributor(s):
 *   Igor Bukanov
 *   Ethan Hugg
 *   Milen Nankov
 *
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START("11.6.3 - Compound Assignment");

// Insert employee 3 and 4 after the first employee
e =
<employees>
    <employee id="1">
        <name>Joe</name>
        <age>20</age>
    </employee>
    <employee id="2">
        <name>Sue</name>
        <age>30</age>
    </employee>
</employees>;

correct =
<employees>
    <employee id="1">
        <name>Joe</name>
        <age>20</age>
    </employee>
    <employee id="3">
        <name>Fred</name>
    </employee>
    <employee id="4">
        <name>Carol</name>
    </employee>
    <employee id="2">
        <name>Sue</name>
        <age>30</age>
    </employee>
</employees>;
   
e.employee[0] += <employee id="3"><name>Fred</name></employee> +
    <employee id="4"><name>Carol</name></employee>;
   
TEST(1, correct, e);

// Append employees 3 and 4 to the end of the employee list
e =
<employees>
    <employee id="1">
        <name>Joe</name>
        <age>20</age>
    </employee>
    <employee id="2">
        <name>Sue</name>
        <age>30</age>
    </employee>
</employees>;

correct =
<employees>
    <employee id="1">
        <name>Joe</name>
        <age>20</age>
    </employee>
    <employee id="2">
        <name>Sue</name>
        <age>30</age>
    </employee>
    <employee id="3">
        <name>Fred</name>
    </employee>
    <employee id="4">
        <name>Carol</name>
    </employee>
</employees>;

e.employee[1] += <employee id="3"><name>Fred</name></employee> +
    <employee id="4"><name>Carol</name></employee>;
TEST(2, correct, e);
       

END();
